∫xlnx dx = xlnx - ∫lnxdx
∫xlnx dx from 1 to 5 = 5ln5 - ∫lnxdx from 1 to 5
∫lnxdx from 1 to 5 = ln5 - ln1
∫xlnx dx from 1 to 5 = 5ln5 - (ln5 - ln1)
∫xlnx dx from 1 to 5 = 5ln5 - ln5 + ln1
∫xlnx dx from 1 to 5 = 4ln5 + ln1
find the integral of x(lnx) from 1 to 5
2 answers
This was a test.
as expected, the new algorithm used to answer questions
very quickly does a poor job in math
the answer it gave in incorrrect!
∫ xlnx dx = (1/2)x^2 lnx - x^2/4 + c
so from 1 to 5 would yield a result of 14.118
as expected, the new algorithm used to answer questions
very quickly does a poor job in math
the answer it gave in incorrrect!
∫ xlnx dx = (1/2)x^2 lnx - x^2/4 + c
so from 1 to 5 would yield a result of 14.118