Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Find the instantaneous rate of change for the function at the given value. f(x)=x^2+2x at x=-4Asked by Sara
Find the instantaneous rate of change for the function at the given value.
f(x)=5x+9 at x=2
f(x)=5x+9 at x=2
Answers
Answered by
Damon
the slope is 5 everywhere !
Answered by
Reiny
Since this is a linear function, the instantanious rate of change will be a constant,
namely the slope of the line, which is 5
I will be 5 no matter what x you choose
namely the slope of the line, which is 5
I will be 5 no matter what x you choose
Answered by
Sara
Thank you so to show work would I just plug in multiple different x-values
Answered by
Sara
3t^2+6 at t=4???
Answered by
oobleck
d/dt (3t^2+6) = 6t
so, at t=4, that would be 24
so, at t=4, that would be 24
Answered by
Damon
Ah, Now we have a parabola.
That is not pre- calc
It is calc
3t^2+6 at t=4???
if y = 3 t^2 + constant
then
dy/dt = slope = 6 t
at t = 4
dy/dt = 6*4 = 24
now if you are not supposed to know that you could plug in
at t = 4, y = 3*16 + 6 = 54
at t = 4.1 y = 3* 16.81 + 6 = 56.43
change in y = 2.43
change in x = 0.1
slope = 2.43 / .1 = 24.3
if you chose t = 4.001, you would get closer to 24
That is not pre- calc
It is calc
3t^2+6 at t=4???
if y = 3 t^2 + constant
then
dy/dt = slope = 6 t
at t = 4
dy/dt = 6*4 = 24
now if you are not supposed to know that you could plug in
at t = 4, y = 3*16 + 6 = 54
at t = 4.1 y = 3* 16.81 + 6 = 56.43
change in y = 2.43
change in x = 0.1
slope = 2.43 / .1 = 24.3
if you chose t = 4.001, you would get closer to 24
Answered by
Sara
I am in pre-calc I guess my teacher is going ahead
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.