Question

find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(N)=1+(n-1)(-4.1)

Answer 1

To find the first, fourth, and tenth terms of the arithmetic sequence described by the rule A(n) = 1 + (n-1)(-4.1), we use the formula for the nth term of an arithmetic sequence:

A(n) = a + (n-1)d

Where:
A(n) = the nth term
a = the first term
d = the common difference
n = the position of the term in the sequence

1. Finding the first term (n=1):
A(1) = 1 + (1-1)(-4.1)
A(1) = 1

Therefore, the first term of the sequence is 1.

2. Finding the fourth term (n=4):
A(4) = 1 + (4-1)(-4.1)
A(4) = 1 + 3(-4.1)
A(4) = 1 - 12.3
A(4) = -11.3

Therefore, the fourth term of the sequence is -11.3.

3. Finding the tenth term (n=10):
A(10) = 1 + (10-1)(-4.1)
A(10) = 1 + 9(-4.1)
A(10) = 1 - 36.9
A(10) = -35.9

Therefore, the tenth term of the sequence is -35.9.