Find the exact value of cot(arcsin(12/13))
and
cos(arcsin(1.7/2))
I know that cos(arcsin(x))=sin(arccos(x))=sqrt(1-x^2). I'm having more difficulty with the first one. Please help! Thank you
3 answers
I got the second answer. Still confused on the first one.
draw your triangle You have the opposite leg=12 and the hypotenuse=13
So, the adjacent leg is √(169-144) = 5
cot(x) = 5/12
So, the adjacent leg is √(169-144) = 5
cot(x) = 5/12
300