Find the exact value of cot(arcsin(12/13))

Question

and
cos(arcsin(1.7/2))

I know that cos(arcsin(x))=sin(arccos(x))=sqrt(1-x^2). I'm having more difficulty with the first one. Please help! Thank you

Answer 1

I got the second answer. Still confused on the first one.

Answer 2

draw your triangle You have the opposite leg=12 and the hypotenuse=13

So, the adjacent leg is √(169-144) = 5

cot(x) = 5/12

Answer 3

300