Find the equation of the tangent line to the curve y=5xcosx at the point (pi,–5pi).

The equation of this tangent line can be written in the form y=mx+b where

m=

and b=

1 answer

y=5x cos x
y'=slope m= 5cosx-5xsinx at x=pi
y'=m=-5

line equation: y= -5x+b
now to find b, you know the point(PI,-5PI) is on it, so

-5pi--5PI+b so b=0
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