take the generic straight line:
y=mx + b.
Put in the first point: (4,4)
4=4m+b let this be the equation 1)
put in the second point in the generic
0=2m+b
Now you have two equations, and two unknowns (m,b). Solve them. In this case subtract the second equation from the first, which yields
4=2m or m=2
This makes b=-4 check that.
Find the equation of the straight line joining
a)(4, 4) and ( 2, 0)
b)(3, -1), (5, 4)
i also need to know how you went about solving this problem so i can understand.. many thanks
2 answers
A slight variation of bobpursey's method for #2
slope = (4+1)/(5-3) = 5/2
let the equation be y = (5/2)x + b
sub in the point (5,4)
4 = 5/2(5) + b
8 = 25 + 2b
b = -17/2
so y = (5/2)x - 17/2
slope = (4+1)/(5-3) = 5/2
let the equation be y = (5/2)x + b
sub in the point (5,4)
4 = 5/2(5) + b
8 = 25 + 2b
b = -17/2
so y = (5/2)x - 17/2
1 answer