Rewrite it as y = -(1/3)x -12
That tells you that the slope of the original line is -1/3. The slope of the perpendicular line must be 3, because the product of the two slopes must be -1.
Since the new line passes through the origin, its equation is just y = 3x
Find the equation of the line that pass through the given point and is perpendicular to the given line. Write in slope intercept form.
(0,0), y + 3x = -12
would I subtract 3x from both sides?
if so would the slope be -3x?
m = 1/3 , (0,0)
y-y1, m(x-x1)
y-0=1/3(x-0)
y-0=1/3 x+0
y-0+0=1/3x
this is where i get lost.
any help please
1 answer
1 answer