Find the equation of the line parallel to the line 3x + y = 5 and containing the point (4, – 2)

Answer 1

Take your original equation (3x+y=5) and put it in y=mx+b form. You should get y=-3x+5. The slope is 3.

What's the slope of a line that is parallel to y=-3x+b? Do you have a point to substitute into that equation to get a y-intercept?

Answer 2

Would these be the points from the original equation?(4, – 2)

I also have some possible answers
A. y = -3x - 2
B. y=-3x+10
C. y=1/3x-10/3
D. y=3x-14

I say it's B but am not sure

Answer 3

Yes, that would be the point to use, and yes, it's B.

y = -3x + b
(-2) = -3(4) + b
-2 = -12 + b
10 = b

C and D couldn't even be possibilities because their slopes are not -3. A doesn't work once you plug in the point.

Answer 4

Thanks Amy!

Answer 5

thanks Amy.