find the equation of a straight line on which the perpendicular from the origin makes an angle of 30 degree with the x-axis and which forms a triangle of are 50/root3 with the axes

Answer 1

if the base has length x,
area = 1/2 * x * x√3 = √3/2 x^2 = 50/√3
x = 10
so, y = 10√3

so, the line is

x/10 + y/(10√3) = 1

Answer 2

oops. x = 10/√3
y = 10

x/(10√3) + y/10 = 1