given line 3x+y=6.
slope=-3.slope of another line is 1/3.
slope point equation (y-Y)=m(x-X).
given point (-2,3).
y-3=1/3(x+2).
3y-9=x+2.
x-3y+11=0
The axes being inclined at an angle of 30°, find the equation to the straight line
which passes through the point(-2,3) and is perpendicular to the straight line
y + 3x = 6
1 answer