Find the enthalpy for : 4Fe + 3O2 = 2Fe2O3

Question

I got the following informations:
Fe + 3H2O = Fe(OH)3 + 3/2H2 - Enthalpy is 160.9 kj
H2 + 1/2O2 = H2O - Enthalpy is -285.8 kj
Fe2O3 + 3H2O = 2Fe(OH)3 - Enthalpy is 288.6

I try using Hess Law but cannot solve it. Can anyone help me find the enthalpy? Thanks

Answer 1

I think you multiply equation 1 by 4.
Reverse equation 3 and multiply by 2.
Add in equation 2 multiplied by 6.