Find the enthalpy change of the following reactions 2C+2H2O---> CO2+CH4

Using the following reactions with their change in H values.
C+H2O---->CO+H2 H=+131.1kjmol-1
Co+H2O---->CO2+H2. H=-41.2kjmol-1
CH4+H2O--->CO+3H2 H=15.3

1 answer

Multiply equation 1 by 2.
Add in equation 2.
Add in the reverse of equation 3.

When you multiply equations multiply dH also. When you reverse an equation, change the sign of dH.
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