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calculate enthalpy of H for the reaction

N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l)

Given the reactions
N2H4(l) + O2(g) -> N2(g) + 2H2O(l) Enthalpy of H = -6.22.2 kJ

H2(g) + (1/2)O2(g) -> H2O(l) enthalpy of H = -285.8 kJ/mol

H2(g) + O2(g) -> H2O2(l) enthalpy of H = -187.8 kJ

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