Find the domain of f(x)\sqrt(2x^(2)-50)

Answer 1

To find the domain of the function f(x) = √(2x^2 - 50), we need to determine the values of x for which the expression under the square root (√(2x^2 - 50)) is non-negative.

The expression under the square root must be greater than or equal to zero:
2x^2 - 50 ≥ 0
2x^2 ≥ 50
x^2 ≥ 25
x ≥ ±5

Therefore, the domain of the function f(x) = √(2x^2 - 50) is all real numbers such that x is greater than or equal to -5 and less than or equal to 5, or in interval notation: [-5, 5].