find the domain:

Question

1/(x^2+2x-3)=square root of x

Answer 1

the denominator cannot be zero,
so x^2 + 2x-3 = (x+3)(x-1)
so x ≠ -3 or x ≠ 1

also in √x , x ≥ 0

so the domain would be the set of real numbers such that
x ≥ 0, x ≠-3, 1

I leave it up to you to write that in the notation that was taught to you.