Find the distance between the two points rounding to the nearest tenth (if necessary).

(3,−4) and (9,−9)

1 answer

To find the distance between the two points \((3, -4)\) and \((9, -9)\), we can use the distance formula:

\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

Where \((x_1, y_1)\) and \((x_2, y_2)\) are the coordinates of the two points. Here, we have:

  • \(x_1 = 3\)
  • \(y_1 = -4\)
  • \(x_2 = 9\)
  • \(y_2 = -9\)

Now, substitute the values into the formula:

\[ d = \sqrt{(9 - 3)^2 + (-9 - (-4))^2} \]

Calculating the differences:

\[ d = \sqrt{(6)^2 + (-9 + 4)^2} \]

This simplifies to:

\[ d = \sqrt{(6)^2 + (-5)^2} \]

Now calculate the squares:

\[ d = \sqrt{36 + 25} \]

Adding the two values:

\[ d = \sqrt{61} \]

Now we can find the numerical value:

\[ d \approx 7.8102 \]

Rounding to the nearest tenth, we find:

\[ d \approx 7.8 \]

Thus, the distance between the two points is approximately 7.8 units.