Find the distance between the two points rounding to the nearest tenth (-5,5) (4,-7)

Answer 1

To find the distance between the points $(-5,5)$ and $(4,-7)$, we can use the distance formula:

$$d=\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2}$$

Here, $(x_1,y_1)=(-5,5)$ and $(x_2,y_2)=(4,-7)$.

Now, substitute the coordinates into the formula:

$$d=\sqrt{(4-(-5){)}^2+(-7-5{)}^2}$$

Calculate $x_2-x_1$ and $y_2-y_1$:

$$x_2-x_1=4+5=9$$ $$y_2-y_1=-7-5=-12$$

Now substitute these values back into the formula:

$$d=\sqrt{(9{)}^2+(-12{)}^2}$$ $$d=\sqrt{81+144}$$ $$d=\sqrt{225}$$ $$d=15$$

Thus, the distance between the two points is $15$. Since $15$ rounded to the nearest tenth is still $15.0$, we can present the final answer as:

$$\boxed{{\displaystyle 15.0}}$$