x^2+y^2-8x+1=34
complete the square
x^2 - 8x + .... + y^2 = 33
x^2 - 8x + 16 + y^2 = 33+16
(x - 4)^2 + (y - 0)^2 = 49
so the centre is (4,0) and the radius = 7 ---> diameter is 14
find the diameter and center of the following circle
x^2+y^2-8x+1=34
1 answer