let s= u/v
then s'= d(u/v)= u'/v -uv'/v^2
You can easily get u'and v'from the expression
u= 9-12x u'=-12
v= x/3-14 v'=1/3
check my thinking.
Find the derivative. Simplify as much as possible.
s(x)=(9-12x)/[(x/3)-(1/4)]
Can someone explain this to me
2 answers
Actually the function reduces to
s(x) = -36, x not equal to 3/4
so s'(x) = 0
s(x) = -36, x not equal to 3/4
so s'(x) = 0