Find the derivative. Simplify as much as possible.

s(x)=(9-12x)/[(x/3)-(1/4)]

Can someone explain this to me

2 answers

let s= u/v

then s'= d(u/v)= u'/v -uv'/v^2

You can easily get u'and v'from the expression

u= 9-12x u'=-12
v= x/3-14 v'=1/3

check my thinking.
Actually the function reduces to
s(x) = -36, x not equal to 3/4

so s'(x) = 0
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