I got up to here.
f'(x)= 3(x+3)^2(x8)^5(d/dx(x))+5(x+3)^3(x-8)^4
Find the derivative of the following function showing your work and fully simplifying your answer. Show steps please! Thank you!!!!!!
f(x)=(x+3)^3(x-8)^5
2 answers
d/dx(x) = dx/dx = 1
So, how come you included it in d/dx (x+3) but not in d/dx (x-8)?
Your work so far is correct.
3(x+3)^2(x-8)^5(d/dx(x))+5(x+3)^3(x-8)^4
3(x+3)^2(x-8)^5 + 5(x+3)^3(x-8)^4
Now factor out some stuff:
(x+3)^2 (x-8)^4 (3(x-8)+5(x+3))
(x+3)^2 (x-8)^4 (8x-9)
So, how come you included it in d/dx (x+3) but not in d/dx (x-8)?
Your work so far is correct.
3(x+3)^2(x-8)^5(d/dx(x))+5(x+3)^3(x-8)^4
3(x+3)^2(x-8)^5 + 5(x+3)^3(x-8)^4
Now factor out some stuff:
(x+3)^2 (x-8)^4 (3(x-8)+5(x+3))
(x+3)^2 (x-8)^4 (8x-9)