recall that the derivative of cos^-1 (x) or arccos (x) is
-1/[sqrt(1-x^2)] * dx
thus the derivative of cos^-1 (x^2)
-(2x)/[sqrt(1 - x^4)]
note that the 2x is the dx that came from the derivatice of the term inside the cos^-1, which is x^2.
hope this helps~ :)
Find the derivative of
f(x) =cos^-1(x^2)
Ok so I'm having a little confusion with the chain rule and I'm not sure if my answer is right...
will the answer be... 2x(-cos^-2(x^2)(-sin(x^2)?
3 answers
In google type:
calc101
When you see list of results click on first link.
When page be open click option derivatives.
When that page be open in rectangle type your function and click option DO IT.
You will see solution step by step.
calc101
When you see list of results click on first link.
When page be open click option derivatives.
When that page be open in rectangle type your function and click option DO IT.
You will see solution step by step.
If cos^-1(x^2) mean 1/cos(x^2)
type cos[x^2]^(-1)
If cos^-1(x^2) mean arccos(x^2)
type arccos[x^2]
type cos[x^2]^(-1)
If cos^-1(x^2) mean arccos(x^2)
type arccos[x^2]
0 answers