Question
Also can I get some help with this LONG, TIRESOME PROBLEM?
Find the derivative using the chain rule.
f(x)= ((3x-7)/(6x+3))^4
Thanks a lot!
(68/(12x^2+12x+3))*[(3x-7)/(6x+3)]^3
you should double check the answer
multiply 4((3x-7)/(6x+3))^3 by the derivative of (3x-7)/(6x+3), which you can find using the quotient rule
that was so right!! thank you so much, i really appreciate all your help!
Yes, the quotent rule is the way to go. You previously asked to use the chain rule, a onerous, tiresome way.
Find the derivative using the chain rule.
f(x)= ((3x-7)/(6x+3))^4
Thanks a lot!
(68/(12x^2+12x+3))*[(3x-7)/(6x+3)]^3
you should double check the answer
multiply 4((3x-7)/(6x+3))^3 by the derivative of (3x-7)/(6x+3), which you can find using the quotient rule
that was so right!! thank you so much, i really appreciate all your help!
Yes, the quotent rule is the way to go. You previously asked to use the chain rule, a onerous, tiresome way.
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