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Find the derivative of 4sinx(6cosx+9sinx) at x=¦Ð/6.
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The equation of the tangent line to y=f(x) at a=2 can be written in the form y=mx+b where f(x) =4sinx/4sinx+6cosx
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Let f(x)=9sinx/2sinx+4cosx.
Then 'f(x)= ((2sinx+4cosx)(9cosx)-(9sinx)(2cosx-4sinx))/(2sinx+4cosx)^2. The equation of the tangent
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Find the derivative of y=4sinx−2cosx
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Find the derivative of
y=4sinx−2cosx
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