The midpoint M = (H+X)/2 = (3,2)
why would you think -3? you know it has to be between -1 and 7, right?
Find the coordinates of the midpoint of HX given that H(-1,3) and X(7,1).
(3,1)
(0,4)
(-3,1)
(-4,0)
i think its (-3,1)
plz check my answer
2 answers
How did you get that ???, but it is wrong
midpoint = ( sum of the x's/2 , sum of the y's / 2), that is, the average of the x and y values.
so midpoint = ( (-1+7)/2 , (3+1)/2 )
= (3, 2)
btw, none of the given choices would be correct, and the subject is "geometry" not geomatry
midpoint = ( sum of the x's/2 , sum of the y's / 2), that is, the average of the x and y values.
so midpoint = ( (-1+7)/2 , (3+1)/2 )
= (3, 2)
btw, none of the given choices would be correct, and the subject is "geometry" not geomatry