Find the coordinates of a point that is in Quadrant IV and is √45 units away from the point (-4, 1).The coordinates are ( , )

Answer 1

Any point on the circle
(x+4)^2 + (y-1)^2 = 45
will do.
To make it easy, consider a 3-4-5 right triangle, scaled up to
27-36-45

So ((-4+27),(1-36)) = (31,-35) will work.