y = 2x-x^2
y' = 2-2x
so, where is 2-2x = 2?
find the co-ordinates
y=x(2-x) where the gradient is 2
2 answers
the gradient is the slope of the tangent to the curve. y' (x) gives the slope of the tangent for any value of x.
So, at x=0, y'(x) = 2-0 = 2, so the gradient is 2 at the point (0,2)
See the graphs at
http://www.wolframalpha.com/input/?i=plot+y%3D2x-x^2%2Cy%3D2x
So, at x=0, y'(x) = 2-0 = 2, so the gradient is 2 at the point (0,2)
See the graphs at
http://www.wolframalpha.com/input/?i=plot+y%3D2x-x^2%2Cy%3D2x