The coordinates of the midpoint of the line AB are (1, 2). The length of the line AB is 10 units.

Question

(a) If the gradient of AB is 0, find the coordinates of A and B

(b) If the gradient of AB is 34 , find the coordinates of A and B.

Answer 1

The first part I already answered in your previous post.

If the gradiant is 34, the diameter is quite steep.
Lets find its equation:
y = 34x + b
but (1,2) lies on it, so
2 = 34(1) + b
b = -32

y = 34b - 32
the equation of the circle I described in the earlier post is
(x-1)^2 + (y-2)^2 = 25
sub in the equation of the diameter to get your quadratic, solve the quadratic.
You will get the two intersection points A and B

Answer 2

I need help with the first question