Did you make a sketch?
first find their intersection.
I had them intersect at (0,1) and (3,4)
Area = [integral] ((3x)^(1/2) + 1 - x - 1) from 0 to 3
= ((2/9(3x)^(3/2) - x^2/2) from 0 to 2
= (2/9)(9)^(3/2) - 9/2 - (0-0))
= (2/9)(27) - 9/2
= 6 - 9/2 = 3/2
Find the area of the region bounded by the graphs f(x)=sqrt(3x)+1, g(x)=x+1
1 answer
1 answer