Find the area of the region bounded by the curves y=x^(-1/2), y=x^(-2), y=1 and y=3.

You get:
a.) 1/2(sqrt(3)) + 4/3
b.) 2(sqrt(3)) - 8/3
c.) 1/2(sqrt(3) - 32/3
d.) 2(sqrt(3)) - 32/3
e.) 8/3 - 2(sqrt(3))

2 answers

The definite integral of y^-.5-y^-2 evaluated from 1 to 3. I forgot 2sqrt(3)-8/3 choice b
I got the same thing. Working out the other answers, they were either negative or obviously too large of an area for the given bounds, thank you Nade!