Find the area of rectangle ABCD that has vertices (-11,5), (-11,15), (-16,15), and (-16,5)

Answer 1

Without graphing, I could see that you have a pair of vertical and horizontal
lines, so it should be easy to find the length and width.

By the "just look at it" theorem, the base is -11 - (-16) = 5
and the height is 15-5 = 10

so the area is 5*10 or 50 units^2