find the area of a regular hexagon with the side length 4m. round to the nearest tenth

Answer 1

The area of a regular hexagon of side 4m is the same as that of 6 equilateral triangles with side 4m.

Area of an equilateral triangle
A=s²*√(3)/4
=4²*√(3)/4
=4√(3)
For the regular hexagon,
6A=24√(3)