Find the area between the curves y= x^2/2 +2 and y = –x – 3 on the interval –4 ≤ x ≤ 4.

Question

I got 40/3 is that correct?

Answer 1

integral (x^2/2 + x + 5)dx

x^3 /6 + x^2/2 + 5 x at 4 minus at -4

64/6 + 8 + 20 - ( -64/6 + 8 -20 )

64/3 + 20 + 40

64/3 + 180/3 = 244/3 = 81 1/3

Answer 2

64/6 + 8 + 20 - ( -64/6 + 8 -20 )
64/3 + 0 + 40
184/3