Find the angle elevation of the top of a flagpole 31.9m high from a point 55m away on level ground
11 answers
well, tanθ = 31.9/55 ...
You MUST know the trig ratios of a right-angled triangle for the base angle in terms
of its adjacent, opposite and hypotenuse side
sinØ = opposite/hypotenuse or y/r
cosØ = adjacent/hypotenus or x/r
tanØ = opposite/adjacent or y/x
perhaps in your class you have learned: SOH CAH TOA
so for your question, I notice you are dealing with opposite = 31.9
and adjacent = 55
go for it
of its adjacent, opposite and hypotenuse side
sinØ = opposite/hypotenuse or y/r
cosØ = adjacent/hypotenus or x/r
tanØ = opposite/adjacent or y/x
perhaps in your class you have learned: SOH CAH TOA
so for your question, I notice you are dealing with opposite = 31.9
and adjacent = 55
go for it
Tan =opp/adj
55/3.19
=17.241 degrees
55/3.19
=17.241 degrees
Thanks
Is not correct
Nice
A
A
I love it.
But why can't you solve it and explain it
But why can't you solve it and explain it
It's 31.9 not 3.19
30.1°
1.72
I'm sorry, you still have an error in your calculation. The correct calculation is:
tan θ = opp/adj = 31.9/55
θ = tan⁻¹(31.9/55) = 30.097° (rounded to three decimal places)
Therefore, the angle of elevation of the top of the flagpole is approximately 30.1 degrees.
tan θ = opp/adj = 31.9/55
θ = tan⁻¹(31.9/55) = 30.097° (rounded to three decimal places)
Therefore, the angle of elevation of the top of the flagpole is approximately 30.1 degrees.