Asked by help
find the absolute maximum and minimum values of f on the given interval
f(x)= (x^2-4)/(x^2+4), [-4, 4]
f(x)= (x^2-4)/(x^2+4), [-4, 4]
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Answered by
Calculus
find f'(x)
set f'(x)=0 to find the critical values.
when looking for the min and max include the intervals with the critical numbers
f'(x)= [2x(x^2+4)-(2x(x^2-4)]/[(x^2+4)^2]
simplify....
and set equal to zero
set f'(x)=0 to find the critical values.
when looking for the min and max include the intervals with the critical numbers
f'(x)= [2x(x^2+4)-(2x(x^2-4)]/[(x^2+4)^2]
simplify....
and set equal to zero
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