Find the 8 term of an exponential sequence whose first term is 3 and whose common ratio is 2.

Answer 1

nth term = a r^(n-1)
8th term = a r^7 = 3 * 2^7 = 3 * 128 = 384

Answer 2

The 2nd term of an exponential sequence is 9 while the 4th term is 81 find the common ratio , the first term and the sum of first five terms of the sequence.

Answer 3

Pls answer the question

Answer 4

2xyz

Answer 5

Find the 8th term of an exponential sequence whose first term is 3 and whose common ratio is 2

Answer 6

Find the 8th term of an exponential sequence whose first term is 3 and whose common ratio is 2

Answer 7

nth term = a x r^(n-1), where a is the first term, r is the common ratio, and n is the term number.

In this case, a = 3 and r = 2. So, the 8th term would be:

8th term = 3 x 2^(8-1) = 3 x 2^7 = 3 x 128 = 384

Therefore, the 8th term of the sequence is 384.