(x + 9) / x = (x + 22.5) / (x + 9)
x^2 + 18 x + 81 = x^2 + 22.5 x
81 = 4.5 x
a1, a2, 18, 27, 40.5
The fifth of an exponential sequence (GP) is greater than the fourth term by 13.5 and fourth term is greater than the thrid by 9.Find:common ratio and the first term.
18 answers
ar^4 - ar^3 = 13.5
ar^3(r - 1) = 13.5 **
ar^3 - ar^2 = 9
ar^2(r-1) = 9 ***
divide ** by ***
r = 13.5/9 = 1.5
sub into ***
a(1.5)^2 (1.5-1) = 9
a(1.125) = 9
a = 9/1.125 = 8
first term is 8, common ratio = 1.5 or 3/2
check:
the terms are:
8, 12, 18, 27, 40.5, ...
term5 - term4 = 40.5-27 = 13.5 , good!
term4 - term3 = 27-18 = 9 , as it should be!
ar^3(r - 1) = 13.5 **
ar^3 - ar^2 = 9
ar^2(r-1) = 9 ***
divide ** by ***
r = 13.5/9 = 1.5
sub into ***
a(1.5)^2 (1.5-1) = 9
a(1.125) = 9
a = 9/1.125 = 8
first term is 8, common ratio = 1.5 or 3/2
check:
the terms are:
8, 12, 18, 27, 40.5, ...
term5 - term4 = 40.5-27 = 13.5 , good!
term4 - term3 = 27-18 = 9 , as it should be!
very, very, very correct
Reiny u are very very good
Very very good!!
That helped me a lot
That helped me a lot
Excellently wonderful, bravo reiny, keep it up.
Excellently wonderful, bravo reiny, keep it up.
Thank you guys π₯Ίπ!! I know this was written 3 years ago, and thanks for telling me how good I am at math. This is very very late, but thanks I appreciate it. *Hands out cookies πͺ*
Great job Reinyππππ!!
Great work! Thanks alot.
Great
Reiny you are very very good at maths pls keep it up
Verry great Reiny keep up the good work.
Bravo it really helped me
I don't understand how a (1.125) = 9
So I don't understand from there
I don't really understand how you gotar^3(r-1)
Thanks Renny