Find the 7th term of geometric progression if the second term is 75, the 5th term,3/5.

Answer 1

using our definitions,

ar = 75
ar^4 = 3/5
divide the 2nd by the 1st:
r^3 = 3/375 = 1/125
r = 1/5

back in ar = 75
a(1/5) = 75
a = 375

term7 = ar^6
= 375(1/15625)
= 3/125

check my arithmetic