Find te equation in slope-intercept form of the line that is the perpendicular bisector of the segment between (-3,4) and (3,-8).

Answer 1

find the midpoint ((-3+3)/2, (4-8)/2)
I think that is 0,-2 check it.

now find the slope: changey/changex
slope= 4+8 / -3-3= 12/-6=-2

perpendicular slope= 1/2 (negative reciprocal).
So the question now is find the equation of the line with slope 1/2, and has the point 0,-2 in it

y=mx+b
put in m, y, and x, solve for b, and you have the line
y=mx + b