Find real numbers x and y such that 3x+2iy-ix+5y=7+5i

3x+2iy-ix+5y=7+5i
i(2y-x) + (3x+5y) = 7 + 5i

the real components must be equal ---> 3x+5y = 7
the imaginary parts must be equal ----> 2y-x = 5

solve these two equations for x and y

Y=2 x=1

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find real number x and y
3x+2iy-ix+5y=7+5i
i(2y-x)+(3x+5y)=7+5i
2y-x=5
3x+5y=7
y=2,x=-1

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