Find ka of h3o+ +C6H706-\ Hc6H706 + H2O assuming HC6H7O6 is aqueous

Answer 1

The dissociation of HC6H7O6 in water can be represented by the equation:

HC6H7O6 (aq) + H2O (l) <-> H3O+ (aq) + C6H7O6- (aq)

From this equation, it can be seen that the equilibrium constant Ka is equal to:

Ka = [H3O+][C6H7O6-] / [HC6H7O6]

where [ ] represents the molar concentration of each species.

Therefore, Ka = [H3O+][C6H7O6-] / [HC6H7O6]

The value of Ka can be determined experimentally or calculated using the concentrations of the species at equilibrium.