delta T = i*Kf*m
So if Kf is he same and m is the same you can forget about K and m. Differences will be due only to i. i is the van't Hoff factor and
i = # particles on dissociation; e.g., LiNO3 will be 2 and that will have the highest freezing point of the three listed. Do you know i for the others?
Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points: Li2SO4 K3PO4 LiNO3
2 answers
LiNo3>Li2SO4>K3PO4