The answer to this question is any point (x,y) which lies on the lien.
To find points that lie on the line, substitute any finite value of x, and evaluate y. Present the answer as a coordinate pair (x,y).
For example,
let x=1, y=2x-3=2(1)-3=-1
So (1,-1) is a point on the line (a solution to the linear equation).
Find four solutions for each question and graph the equation.
y=2x-3
2 answers
y=2x-3
When x=0
y=2(0)-3
y=0-3
y= -3
When x=1
y=2(1)-3
y=2-3
y= -1
When x=2
y=2(2)-3
y=4-3
y= 3
When x=3
y=2(3)-3
y= 6-3
y=3
The four solutions are:-
(0,3) (1,-1) (2,3) (3,3)
As the solutions have been found draw a graph and plot them.
When x=0
y=2(0)-3
y=0-3
y= -3
When x=1
y=2(1)-3
y=2-3
y= -1
When x=2
y=2(2)-3
y=4-3
y= 3
When x=3
y=2(3)-3
y= 6-3
y=3
The four solutions are:-
(0,3) (1,-1) (2,3) (3,3)
As the solutions have been found draw a graph and plot them.
3 answers