If " n " is an integer, then n, n + 2, n + 4 and n + 6 will be even consecutive integers.
Four times the greatest is 36 more than more than the sum of the other three.
This mean :
4 ( n + 6 ) = 36 + ( n + n + 2 + n + 4 )
4 ( n + 6 ) = 36 + ( n + n + 2 + n + 4 )
4 * n + 4 * 6 = 36 + 3 n + 2 + 4
4 n + 24 = 42 + 3 n Subtract 3 n to both sides
4 n + 24 - 3 n = 42 + 3 n - 3 n
n + 24 = 42 Subtract 24 to both sides
n + 24 - 24 = 42 - 24
n = 18
So consecutive even integers are :
18
18 + 2 = 20
18 + 4 = 22
18 + 6 = 24
Proof :
4 * 24 = 36 + 18 + 20 + 22
96 = 96
Find four consecutive even integers such that four times the greatest is 36 more than more than the sum of the other three.Four times a number increased by 5 is 37.Find the number.
1 answer