Asked by Jax
find three consecutive odd integers such that the sum of the first and the second is 201 less the square of the third
Answers
Answered by
Steve
the numbers are x,x+2,x+4
x + x+2 = (x+4)^2 - 201
Now just expand, collect terms, and solve the quadratic.
x + x+2 = (x+4)^2 - 201
Now just expand, collect terms, and solve the quadratic.
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