f(x) = 3e^x -2x^2 + c
10 = 3e^0 -2(0)^2+ c
10 =3-0+ c
7= c
F(x) = 3e^x -2x^2 + 7
Find f(x) by solving the initial value problem.
f '(x) = 3ex - 4x; f(0) = 10
f(x) =
1 answer
f '(x) = 3ex - 4x; f(0) = 10
f(x) =
1 answer