first two correct.
(f-g)(x)=f(x)-g(x)
16-4+3 -16-8+7
-12+10=-2
check that.
find f(-3) for f(x)= 3x-x^2
f(-3)=0
f(-3)=18
f(-3)=-18<---
f(-3)=-15
What is the range of f(x)?
f(x)=|x+1|
All real numbers greater than 0
All real numbers greater than -1
All real numbers greater than or equal to 0<-
All real numbers greater than or equal to -1
f(x)=4x^2-2x+3 ; g(x)=2x^3+4x-7
What is the value of (f-g)(2)?
6
10
5
8<-
5 answers
10? Okay im lost.
3rd one:
f(x)=4x^2-2x+3 ; g(x)=2x^3+4x-7
(f-g)(x) = 2x^2 - 6x + 10
(f-g)(2) = 8 - 12 + 10 = 6
f(x)=4x^2-2x+3 ; g(x)=2x^3+4x-7
(f-g)(x) = 2x^2 - 6x + 10
(f-g)(2) = 8 - 12 + 10 = 6
forget my previous post, did not notice the x^3
f(x)=4x^2-2x+3 ; g(x)=2x^3+4x-7
(f-g)(x) = 4x^2 - 6x + 10 - 2x^3
(f-g)(2) = 16 - 12 + 10 - 16
= -2
bobpursley was correct
f(x)=4x^2-2x+3 ; g(x)=2x^3+4x-7
(f-g)(x) = 4x^2 - 6x + 10 - 2x^3
(f-g)(2) = 16 - 12 + 10 - 16
= -2
bobpursley was correct
Thanks guys!
1 answer