y=x^-cosx
ln y = -cos x ln x
d/dx( ln y ) = d/dx (-cos x lnx)
(1/y)dy/dx = (-cos x) / x + ln x sin x
dy/dx = [ln x sin x - (1/x) cos x] /y
= [ln x sin x - (1/x) cos x] x^cos x
Find derivative(use logrithmic functions).
y=x^-cosx
2 answers
dy/dx = [ln x sin x - (1/x) cos x] y
= [ln x sin x - (1/x) cos x] x^cos-x
= [ln x sin x - (1/x) cos x] x^cos-x