Knowing that derivative of sinx is cos⁡x and derivative of cosx is -senx, prove by induction, that the 2n derivative of sinx = ((- 1) ^ n ) * sin⁡x⁡ and the 2n derivative of cos⁡x = ((- 1) ^ n)* cos⁡x.

Answer 1

so, check n=1. The 2nd derivative of sinx is -sinx since
d/dx(sinx) = cosx
d/dx(cosx) = -sinx
Now assume it is true for k=2n. What about 2n+2?
y⁽²ⁿ⁾sinx = (-1)ⁿ sinx
y⁽²ⁿ⁺¹⁾sinx = (-1)ⁿ cosx
y⁽²ⁿ⁺²⁾sinx = -(-1)ⁿ cosx = (-1)ⁿ⁺¹ sinx
QED