Find cos theta, given that sin theta=3/5 and theta is in quadrant II

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sinØ = 3/5 , Ø in II

make a sketch of the corresponding right-angled triangle to see that y = 3, r = 5
x^2 + 3^2 = 5^2
x = ± 4, but we are in II , so x = -4

cosØ = -4/5
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