x^2=3y
(x-0)^2=3(y-0)
vertex is (0,0)
line of symmetry is x=0
Graph: the parabola opens upwards and meets at the point (0,0)
Find and label the vertex and the line of symmetry. Graph the function.
f(x)=1/3x^2
1 answer
f(x)=1/3x^2
1 answer